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Q: What is the sum of all the digits from 1-99?

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The sum is 22 times the sum of the three digits.

The sum of all the digits of all the positive integers that are less than 100 is 4,950.

int Sum( int digits ) { if(digits < 10) return digits; return digits%10 + Sum(digits/10); }

1000000

-99

first read nd write all individual digits then goto sum funtion use by adding all individual digits..

Add the digits together. The sum of the digits of 23 is 5.

3+5 = 8

It is 45.

The sum of the digits is also a multiple of 9. And, if the sum of the digits is too large, you can sum those digits and keep going.

...int sum = 0;for (int i = 101; i

199

When the sum of the digits you are adding is 10 or larger.

Add the digits together. The sum of the digits of 23 is 5.

The sum is 154.

the sum of my digits is 6? answer=60

The sum of all the integers between 1,000 and 2,000 is 1,498,500.

The sum of all palindromic numbers from 1001 to 9999 is 495000.

137?

199 If it's 200 rounded to nearest ten, then the number must be between 195 and 205. Only 199 has the correct digit sum.

To round to the nearest hundred and ten both being 200 it leaves 9 possibilities. 195,196,197,198,199,201,202,203, and 204. The only one with digits adding up to 19 is 199.

8 is the same as the sum of the digits of its cube, 512.

The sum of the digits in 252 is 2 + 5 + 2 which equals 9.

-5

The answer to the smallest possible value of the sum of all the digits is 1. the number can either be 100 or 1000 - either way the sum is still one.